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Article Dans Une Revue Theoretical Computer Science Année : 2023

The Maker-Breaker Largest Connected Subgraph Game

Résumé

Given a graph G and k ∈ N, we introduce the following game played in G. Each round, Alice colours an uncoloured vertex of G red, and then Bob colours one blue (if any remain). Once every vertex is coloured, Alice wins if there is a connected red component of order at least k, and otherwise, Bob wins. This is a Maker-Breaker version of the Largest Connected Subgraph game introduced in [Bensmail et al. The Largest Connected Subgraph Game. Algorithmica, 84(9):2533-2555, 2022]. We want to compute cg(G), which is the maximum k such that Alice wins in G, regardless of Bob's strategy. Given a graph G and k ∈ N, we prove that deciding whether cg(G) ≥ k is PSPACEcomplete, even if G is a bipartite, split, or planar graph. To better understand the Largest Connected Subgraph game, we then focus on A-perfect graphs, which are the graphs G for which cg(G) = |V (G)|/2 , i.e., those in which Alice can ensure that the red subgraph is connected. We give sufficient conditions, in terms of the minimum and maximum degrees or the number of edges, for a graph to be A-perfect. Also, we show that, for any d ≥ 4, there are arbitrarily large A-perfect d-regular graphs, but no cubic graph with order at least 18 is A-perfect. Lastly, we show that cg(G) is computable in linear time when G is a P4-sparse graph (a superclass of cographs).
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Dates et versions

hal-03993562 , version 1 (17-02-2023)

Identifiants

Citer

Julien Bensmail, Foivos Fioravantes, Fionn Mc Inerney, Nicolas Nisse, Nacim Oijid. The Maker-Breaker Largest Connected Subgraph Game. Theoretical Computer Science, 2023, 943, pp.102-120. ⟨10.1016/j.tcs.2022.12.014⟩. ⟨hal-03993562⟩
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